Popcorn Hacks

Popcorn Hack 1

Problem:
What will be the result of this expression?

True or False and False

Answer:

  • According to operator precedence, and is evaluated before or.
  • False and False evaluates to False.
  • True or False evaluates to True.

Final Result:

True

Popcorn Hack 2

Problem:
What will be the result of this expression?

not True and False

Answer:

  • not True evaluates to False.
  • False and False evaluates to False.

Final Result:

False

Popcorn Hack 3

Problem:
What will be the result of this expression?

True or False and not False

Answer:

  • not False evaluates to True.
  • False and True evaluates to False.
  • True or False evaluates to True.

Final Result:

True


# Homework Hack 1: Binary Converter

## Decimal to Binary Converter Function:


```python
def decimal_to_binary(decimal):
    if decimal == 0:
        return "0"
    is_negative = decimal < 0
    decimal = abs(decimal)
    binary = ""
    while decimal > 0:
        binary = str(decimal % 2) + binary
        decimal = decimal // 2
    if is_negative:
        return "-" + binary
    return binary

# Example
print(decimal_to_binary(10))   # Output: 1010
print(decimal_to_binary(-5))   # Output: -101


1010
-101

Binary to Decimal Converter Function:

def binary_to_decimal(binary_str):
    is_negative = binary_str.startswith("-")
    if is_negative:
        binary_str = binary_str[1:]
    decimal = 0
    for index, digit in enumerate(reversed(binary_str)):
        if digit == "1":
            decimal += 2 ** index
    if is_negative:
        return -decimal
    return decimal

# Example
print(binary_to_decimal("1010"))   # Output: 10
print(binary_to_decimal("-101"))   # Output: -5


10
-5

Homework Hack 2: Difficulty Level Checker

Corrected Code:

import time

difficulty = input("Enter difficulty (easy, medium, hard): ").lower().strip()

# Corrected logic: use 'and' instead of 'or'
while difficulty not in ["easy", "medium", "hard"]:
    print("Please enter a valid difficulty level.")
    difficulty = input("Enter difficulty (easy, medium, hard): ").lower().strip()
    time.sleep(0.5)

print("Difficulty set to:", difficulty)


Difficulty set to: hard

Explanation of Fix:

The original while condition was wrong because it used or.
Using not in with a list correctly checks if the entered difficulty is not one of the valid options.